The correct answer is $518.4$ . It's given that the area of the original poster is $360$ square inches. Let $l$ represent the length, in inches, of the original poster, and let $w$ represent the width, in inches, of the original poster. Since the area of a rectangle is equal to its length times its width, it follows that $360 equals script l w$ . It's also given that a copy of the poster is made in which the length and width of the original poster are each increased by $20 percent sign$ . It follows that the length of the copy is the length of the original poster plus $20 percent sign$ of the length of the original poster, which is equivalent to $l + \frac{20}{100} l$ inches. This length can be rewritten as $script l plus 0.2 script l$ inches, or $1.2 script l$ inches. Similarly, the width of the copy is the width of the original poster plus $20 percent sign$ of the width of the original poster, which is equivalent to $w + \frac{20}{100} w$ inches. This width can be rewritten as $w plus 0.2 w$ inches, or $1.2 w$ inches. Since the area of a rectangle is equal to its length times its width, it follows that the area, in square inches, of the copy is equal to $left parenthesis 1.2 script l right parenthesis left parenthesis 1.2 w right parenthesis$ , which can be rewritten as $left parenthesis 1.2 right parenthesis left parenthesis 1.2 right parenthesis left parenthesis script l w right parenthesis$ . Since $360 equals script l w$ , the area, in square inches, of the copy can be found by substituting $360$ for $l w$ in the expression $left parenthesis 1.2 right parenthesis left parenthesis 1.2 right parenthesis left parenthesis script l w right parenthesis$ , which yields $left parenthesis 1.2 right parenthesis left parenthesis 1.2 right parenthesis left parenthesis 360 right parenthesis$ , or $518.4$ . Therefore, the area of the copy, in square inches, is $518.4$ .